### Умова завдання:

2,1Б.
Дано вектори $\stackrel{\to }{a}=\left(-10;\phantom{\rule{0.147em}{0ex}}-8;\phantom{\rule{0.147em}{0ex}}2\right)$, $\stackrel{\to }{b}=\left(5;\phantom{\rule{0.147em}{0ex}}-7;\phantom{\rule{0.147em}{0ex}}3\right)$, $\stackrel{\to }{c}=\left(7;\phantom{\rule{0.147em}{0ex}}-4;\phantom{\rule{0.147em}{0ex}}-2\right)$ і $\stackrel{\to }{d}=\left(5;\phantom{\rule{0.147em}{0ex}}8;\phantom{\rule{0.147em}{0ex}}-8\right)$.

Обчисли координати даних векторів:

$\stackrel{\to }{a}+\stackrel{\to }{c}=\left(i\phantom{\rule{0.147em}{0ex}};\phantom{\rule{0.147em}{0ex}}i\phantom{\rule{0.147em}{0ex}};\phantom{\rule{0.147em}{0ex}}i\phantom{\rule{0.147em}{0ex}}\right)$
$\stackrel{\to }{a}+\stackrel{\to }{b}+\stackrel{\to }{d}=\left(i\phantom{\rule{0.147em}{0ex}};\phantom{\rule{0.147em}{0ex}}i\phantom{\rule{0.147em}{0ex}};\phantom{\rule{0.147em}{0ex}}i\phantom{\rule{0.147em}{0ex}}\right)$
$\stackrel{\to }{a}+\stackrel{\to }{b}+\stackrel{\to }{c}+\stackrel{\to }{d}=\left(i\phantom{\rule{0.147em}{0ex}};\phantom{\rule{0.147em}{0ex}}i\phantom{\rule{0.147em}{0ex}};\phantom{\rule{0.147em}{0ex}}i\phantom{\rule{0.147em}{0ex}}\right)$